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306=x^2-x
We move all terms to the left:
306-(x^2-x)=0
We get rid of parentheses
-x^2+x+306=0
We add all the numbers together, and all the variables
-1x^2+x+306=0
a = -1; b = 1; c = +306;
Δ = b2-4ac
Δ = 12-4·(-1)·306
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-35}{2*-1}=\frac{-36}{-2} =+18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+35}{2*-1}=\frac{34}{-2} =-17 $
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